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You ll use EEPROM to store long-term data elements These might be things like the serial number, hardware version, firmware version, or things like your EA Protocol Remember the comyourcompanyP1 values I discussed in the first part of the book EEPROM is where you store them It should be obvious to a seasoned programmer that you don t want to hard-code these kinds of values into your program source TIP: When you store values in EEPROM, make sure the routines that access them are generic enough to support future modifications so that you only need change the data, not your source code Let s say you have a protocol named: commynicelittlecompanyp1 Later you want to have a protocol called: commynicelittlecompanyp100, a value that is 2 characters longer than the first one.

pair of sorts, the Area size: is the _smm_min_size (0.1% of the 200MB we have for the pga_aggregate_target), and the Max Area size: is the _smm_max_size (5% of the target). In this case, the data to be sorted from both tables is very small, so there is no I/O cost. (You can also see that there is no estimated Total Temp space used:.) The cost of the join is therefore Outer Outer Inner Inner table table table table data sort data sort acquisition cost + cost (CPU only in this case) + acquisition cost + cost (CPU only in this case)

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To turn the reported Total CPU sort cost into standard units, we divide by 5,000,000 (the 500 MHz * 10,000 microsecond sreadtim) to get Cost of join = 2,517 + 5,018,650 / 5,000,000 + 631 + 5,033,608 / 5,000,000 = 3,148 + 2 and a bit. You can see at the end of the following section that the actual cost quoted for the merge is 3,151, which compares well with the 3,150 plus a bit that I have just calculated. Since I can t guarantee the timing, or direction, of rounding used, I can t be certain whether the difference of one is due to rounding, or to a small cost that is directly attributable to the merge operation itself. SM Join Outer table: resc: 2517 cdn: 68 rcz: 27 deg: 1 resp: 2517 Inner table: PARENT Alias: P resc: 631 cdn: 110 rcz: 27 deg: 1 resp: 631 using join:1 distribution:2 #groups:1 SORT resource Sort statistics Sort width: 58 Area size: 208896 Max Area size: Degree: 1 Blocks to Sort: 1 Row size: 40 Total Rows: Initial runs: 1 Merge passes: 0 IO Cost / pass: Total IO sort cost: 0 Total CPU sort cost: 5018650 Total Temp space used: 0 SORT resource Sort statistics Sort width: 58 Area size: 208896 Max Area size: Degree: 1 Blocks to Sort: 1 Row size: 40 Total Rows: Initial runs: 1 Merge passes: 0 IO Cost / pass: Total IO sort cost: 0 Total CPU sort cost: 5033608 Total Temp space used: 0 Merge join Cost: 3151 Resp: 3151

Don t set up your EEPROM access routines to read based on length as that can easily change A good idea might be to always store EEPROM values as strings with a trailing 0x00 (null) then you could use a single string access routine for all your elements, assuming of course that you don t use 0x00 inside the string Taking the PIC16F690 microcontroller as a specific example, you get 4096 program words, 256 bytes (you read that right, I said bytes ) of SRAM, and 256 bytes of EEPROM The program space (4KWords) is large enough to do pretty much any data capture and transfer to the iPhone Should you want to do some other processing in your controller before passing the data on, that s where you ll have to be careful I already mentioned that my credit card reader accessory utilizes only 55% of the 4KWord memory.

<!-- Most likely not what you want to do --> <Message Text="%40(Compile->'%25(Filename)')%25(Extension): @(Compile->'%(Filename)')%(Extension)"/> </Target> In the first message, you are passing the value @(Compile->'%(Filename)%(Extension)'). The @ character says you are acting upon the list items of the Compile item, and the % character determines which transformations are to be executed. In this case, you have %(Filename)% (Extension). Figure 3-14 shows the output from this message task and for the remainder of the target. We will explain the other items in this target shortly.

10485760 68 0

10485760 110 0

So, if I can do it, you probably can too..

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